034-Java-025

xiaoxiao2021-02-28  72

解析字符串为时间

SimpleDateFormat 类有一些附加的方法,特别是parse(),它试图按照给定的SimpleDateFormat 对象的格式化存储来解析字符串

import java.util.*; import java.text.*; public class DateDemo { public static void main(String args[]) { SimpleDateFormat ft = new SimpleDateFormat ("yyyy-MM-dd"); String input = args.length == 0 ? "1818-11-11" : args[0]; System.out.print(input + " Parses as "); Date t; try { t = ft.parse(input); System.out.println(t); } catch (ParseException e) { System.out.println("Unparseable using " + ft); } } } Java休眠

import java.util.*; public class SleepDemo { public static void main(String args[]) { try { System.out.println(new Date( ) + "\n"); Thread.sleep(1000*3); // 休眠3秒 System.out.println(new Date( ) + "\n"); } catch (Exception e) { System.out.println("Got an exception!"); } } }

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