05-树8 File Transfer (25分)

xiaoxiao2021-02-28  101

We have a network of computers and a list of bi-directional connections. Each of these connections allows a file transfer from one computer to another. Is it possible to send a file from any computer on the network to any other?

Input Specification:

Each input file contains one test case. For each test case, the first line contains NN (2\le N\le 10^42N104), the total number of computers in a network. Each computer in the network is then represented by a positive integer between 1 and NN. Then in the following lines, the input is given in the format:

I c1 c2

where I stands for inputting a connection between c1 and c2; or

C c1 c2

where C stands for checking if it is possible to transfer files betweenc1 and c2; or

S

where S stands for stopping this case.

Output Specification:

For each C case, print in one line the word "yes" or "no" if it is possible or impossible to transfer files between c1 and c2, respectively. At the end of each case, print in one line "The network is connected." if there is a path between any pair of computers; or "There are k components." where k is the number of connected components in this network.

Sample Input 1:

5 C 3 2 I 3 2 C 1 5 I 4 5 I 2 4 C 3 5 S

Sample Output 1:

no no yes There are 2 components.

Sample Input 2:

5 C 3 2 I 3 2 C 1 5 I 4 5 I 2 4 C 3 5 I 1 3 C 1 5 S

Sample Output 2:

no no yes yes The network is connected.

连通分量问题,采用并查集。

注意:用getchar()消回车!

#include<stdio.h> int tree[10001]; int findroot(int x){ if(tree[x]==-1)return x; return tree[x]=findroot(tree[x]); } int main(){ int n,i,c1,c2; char temp; scanf("%d",&n); int cou=n; getchar(); for(i=1;i<=n;i++){ tree[i]=-1; } while(1){ scanf("%c",&temp); if(temp=='S'){ break; } scanf("%d %d",&c1,&c2); c1=findroot(c1); c2=findroot(c2); if(temp=='I'){ if(c1!=c2){ tree[c1]=c2; } cou--; } else{ if(c1==c2){ printf("yes\n"); } else{ printf("no\n"); } } getchar();//!!!!!!! } if(cou==1){ printf("The network is connected.\n"); } else{ printf("There are %d components.\n",cou); } }

转载请注明原文地址: https://www.6miu.com/read-84270.html

最新回复(0)