PAT basic 1034

xiaoxiao2021-02-28  76

#include <iostream> #include <cstdio> using namespace std; long long int a, b, c, d; //辗转相除法:求最大公约数 long long int gcd(long long int t1, long long int t2) { return t2 == 0 ? t1 : gcd(t2, t1 % t2); }//本来自己写了个,然后超时了= =|| void func(long long int m, long long int n) { int flag1 = 0; int flag2 = 0; if (n == 0) { cout << "Inf"; return ; } if (m == 0) { cout << 0; return ; } if (m < 0) { m = 0 - m; flag1 = 1; } if (n < 0) { n = 0 - n; flag2 = 1; } int flag = 0; if (flag1 == 1 && flag2 == 1) { flag = 0; } else if (flag1 == 1 || flag2 == 1) { flag = 1; } if (m == n) { if (flag == 1) cout << "(-1)"; else cout << "1"; return; } long long int x = m % n; long long int y = m / n; if (x == 0) { if (flag == 0) cout << y; else cout << "(-" << y << ")"; return ; } else { long long int t1 = m - y * n; long long int t2 = n; long long int t = gcd(t1, t2); t1 = t1 / t; t2 = t2 / t; if (flag == 1) { cout << "(-"; if (y != 0) cout << y << " " << t1 << "/" << t2; else cout << t1 << "/" << t2; cout << ")"; } else { if (y != 0) cout << y << " " << t1 << "/" << t2; else cout << t1 << "/" << t2; } } } void add() { long long int m, n; m = a * d + b * c; n = b * d; func(a, b); cout << " + "; func(c, d); cout << " = "; func(m, n); cout << endl; } void min() { long long int m, n; m = a * d - b * c; n = b * d; func(a, b); cout << " - "; func(c, d); cout << " = "; func(m, n); cout << endl; } void multi() { long long int m, n; m = a * c; n = b * d; func(a, b); cout << " * "; func(c, d); cout << " = "; func(m, n); cout << endl; } void div() { long long int m, n; m = a * d; n = b * c; func(a, b); cout << " / "; func(c, d); cout << " = "; func(m, n); cout << endl; } int main() { scanf("%lld/%lld %lld/%lld", &a, &b, &c, &d); add(); min(); multi(); div(); return 0; }
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