js跳转页面方法实现汇总

xiaoxiao2021-02-28  65

代码如下: <span id="tiao">3</span><a href="javascript:countDown"></a>布丁足迹;秒后自动跳转……<meta http-equiv=refresh content=3;url='/search/billsearch.jsp'</ul>  <!--脚本开始-->  <script language="javascript" type="">  function countDown(secs){  tiao.innerText=secs;  if(--secs>0)  setTimeout("countDown("+secs+")",1000);  }  countDown(3);  </script>  <!--脚本结束-->  按钮式:  <INPUT name="pclog" type="button" value="GO" onClick="location.href='http://www.ddhbb.com/'">  链接式:  <a href="javascript:history.go(-1)">返回上一步</a>  <a href="<%=Request.ServerVariables("HTTP_REFERER")%>">返回上一步</a>  直接跳转式:  <script>window.location.href='http://www.ddhbb.com';</script>  开新窗口:  <a href="javascript:" onClick="window.open('http://www.ddhbb.com/blog/guestbook.asp','','height=500,width=611,scrollbars=yes,status=yes')">布丁足迹</a>  JS跳转页面参考代码  第一种:  <script language="javascript" type="text/javascript">  window.location.href="login.jsp?backurl="+window.location.href;  </script>  第二种:  <script language="javascript">  alert("返回");  window.history.back(-1);  </script>  第三种:  <script language="javascript">  window.navigate("top.jsp");  </script>  第四种:  <script language="JavaScript">  self.location='top.htm';  </script>  第五种:  <script language="javascript">  alert("非法访问!");  top.location='xx.jsp';  </script>  =====javascript中弹出选择框跳转到其他页面=====  <script language="javascript">  <!--  function logout()...{  if (confirm("你确定要注销身份吗?是-选择确定,否-选择取消"))...{  window.location.href="logout.asp?act=logout"  -->  </script>  =====javascript中弹出提示框跳转到其他页面=====  <script language="javascript">  <!--  function logout()...{  alert("你确定要注销身份吗?");  window.location.href="logout.asp?act=logout"  -->  </script> 
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