Q:If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below 1000.
A:(python)
x, y, max = map(int, input('what is your arguments?\n').split()) #input().split() map(int, input().split()) input_list = map(int, input().split()) #import sys lines = sys.stdin.;read().splitlines() def sum_of_multiples(x, y, max): sum = 0 if x <= 0 or y <= 0 or max < min(x, y): print('input error!') return 0 if max > x * y: for i in range(1, x*y+1): if i % x == 0 or i % y == 0: sum = sum + i n = int(max / (x * y)) sum = n * (n - 1) / 2 * x * y + n * sum for i in range(n*x*y+1, max+1): sum = sum + i return int(sum) else: for i in range(1, max+1): if i % x == 0 or i % y == 0: sum = sum + i return sum print(sum_of_multiples(x, y, max))
