解决方式就是
FloatBuffer.position(0);//FloatBuffer.flip(); ShortBuffer.position(0);//ShortBuffer.flip();无论如何这难以自圆其说，以下分析纯属扯淡。敬待高论！！
06-08 11:20:09.772 E/Adreno-ES11: <qglDrvAPI_glEnableClientState:1675>: GL_INVALID_ENUM 06-08 11:20:09.794 E/AndroidRuntime: FATAL EXCEPTION: GLThread 3592 Process: com.example.a3d_study_2, PID: 15266 java.lang.ArrayIndexOutOfBoundsException: remaining() < count < needed at com.google.android.gles_jni.GLImpl.glDrawElements(Native Method) at com.example.a3d_study_2.No_4.NonRenderer.onDrawFrame(NonRenderer.java:115) at android.opengl.GLSurfaceView$GLThread.guardedRun(GLSurfaceView.java:1522) at android.opengl.GLSurfaceView$GLThread.run(GLSurfaceView.java:1239)我的现状：目标是要绘制一个正方形。
private FloatBuffer vertexBuffer; private ShortBuffer orderBufferSquare, orderBufferRectange, orderBufferParallelogram; private final float[] vertexArray = { //遵循：右上→右下→左下→左上 的点序。 //First Square 4f, 4f, 0f, 4f, -4f, 0f, -4f, -4f, 0f, -4f, 4f, 0f, //Second rectangle 8f, 7f, 0f, 8f, 6f, 0f, 6f, 6f, 0f, 6f, 7f, 0f, //Third Parallelogram 15f, 13f, 0f, 14f, 9f, 0f, 10f, 9f, 0f, 11f, 13f, 0f, }; private final short[] orderArraySquare = {0, 1, 2, 0, 2, 3}; private final short[] orderArrayRectange = {4, 5, 6, 4, 6, 7}; private final short[] orderArrayParallelogram = {8, 9, 10, 8, 10, 11}; 把定点坐标放到 FloatBuffer 中。 ByteBuffer bbVertex = ByteBuffer.allocateDirect(this.vertexArray.length * 4); bbVertex.order(ByteOrder.nativeOrder()); this.vertexBuffer = bbVertex.asFloatBuffer(); this.vertexBuffer.put(this.vertexArray); ByteBuffer bbOrderSquare = ByteBuffer.allocateDirect(this.orderArraySquare.length * 2); bbOrderSquare.order(ByteOrder.nativeOrder()); this.orderBufferSquare = bbOrderSquare.asShortBuffer(); this.orderBufferSquare.put(this.orderArraySquare);FloatBuffer继承Buffer，并且通过getter/setter方法可以享用父类的参数position，limit等。 limit在ByteBuffer.allocateDirect(this.vertexArray.length * 4)已经确定。 伴随着this.vertexBuffer.put(this.vertexArray);操作 position还会变化为 vertexArray.length
所以执行完上述代码后
vertexBuffer.position == vertexArray.length//12 orderBufferSquare.position == orderArraySquare.length//6 执行到下述代码 @Override public void onDrawFrame(GL10 gl) { // Clears the screen and depth buffer. gl.glClear(GL10.GL_COLOR_BUFFER_BIT | GL10.GL_DEPTH_BUFFER_BIT);// OpenGL docs. gl.glLoadIdentity(); gl.glTranslatef(0, 0, -14); gl.glEnableClientState(GL10.GL_TRIANGLES); gl.glVertexPointer(3, GL10.GL_FLOAT, 0, this.vertexBuffer); gl.glDrawElements(GL10.GL_TRIANGLES, this.orderArraySquare.length, GL10.GL_UNSIGNED_SHORT, this.orderBufferSquare); } }glVertexPointer从 vertexBuffer.position（）处开始读取顶点数据，所以从一开始就没有读到数据(也就是说要绘制的顶点并没有被系统获取到)。这到不会导致报错。 glDrawElements真正要绘制this.orderArraySquare.length个定点所构成的图形时候，就需要从上一步获取到的顶点按this.orderBufferSquare顺序逐个取出来了，发现我们给定的索引导致了 ArrayIndexOutOfBoundsException
