Linux shell脚本中执行命令结果赋值给变量&&echo输出变量是否包含换行符的问题
echo $ret 和 echo "$ret" 区别： 如果是echo $ret，输出结果为一行，没有换行符 如果是echo "$ret"，输出结果为多行，有换行符
# vim test.sh
#!/bin/sh CORE_DIR=`pwd` UI_DIR=$CORE_DIR/../tomcat8 target=$UI_DIR/webapps/ui/META-INF/MANIFEST.MF newline=$'\n' newline2=$newline$newline ret="$newline============ ui Timestamp ===========$newline2" if [ -e $target ]; then ret+="$(cat $target | sed -n '/Timestamp/p' )" else ret+="File or directory not found." fi ret+="$newline2" ret+="$newline============ core Timestamp ===========$newline2" now=`date -I` target_core=$CORE_DIR/logs/$now\.0\.log if [ -e $target_core ]; then ret+="$(grep Timestamp $target_core | sed -n '/Timestamp/p' | sed s'/\ \ \ \ //' | sed s'/"//g')" else ret+="core log file or directory not found." fi ret+=$newline #echo $ret echo "$ret"
