Python二分法 简要示例
从一个列表中查找匹配的数值
#!/usr/bin/env python
# -*- coding:utf-8 -*-
#Author:xp
#blog_url: http://blog.csdn.net/wuxingpu5/article/details/71209731
l=[1,2,10,30,40,33,22,99,31]
l.sort()
print(l)
def search(find_num,seq):
if len(seq) == 0:
print('seq not exists')
return
mid_index=len(seq)//2
mid_num=seq[mid_index]
print(seq, mid_num)
if find_num > mid_num:
seq=seq[mid_index+1:]
search(find_num, seq)
elif find_num < mid_num:
seq=seq[:mid_index]
search(find_num, seq)
else:
print('find it')
search(44,l)
