Problem A: 从点到面

Description

一个矩形可以由左上角和右下角的顶点而唯一确定。现在请定义两个类：Point和Rectangle。

其中Point类有x和y两个属性（均为int类型），表示二维空间内一个点的横纵坐标，并具有相应的构造函数、析构函数和拷贝构造函数。此外，还有getX()和getY()方法用以得到一个点的坐标值。

Rectangle类有leftTop和rightBottom两个属性（均为Point类的对象），表示一个矩形的左上角和右下角的两个点，并具有相应的构造函数、析构函数。此外，还有getLeftTop()、getRightBottom()方法用于获取相应的左上角点、右下角点，getArea()方法用以获取面积。

Input

输入有多行。

第一行是一个正整数M，表示后面有M个测试用例。

每个测试用例占一行，包括4个正整数，分别为左上角的横坐标、纵坐标，右下角的横坐标、纵坐标。

注意：

1.请根据输出样例判断两个类中相应方法的书写方法。

2. 假定屏幕的左下角为坐标原点。

Output

输出见样例。

Sample Input

110 10 20 0

Sample Output

A point (10, 10) is created!A point (20, 0) is created!A rectangle (10, 10) to (20, 0) is created!Area: 100Left top is (10, 10)A point (20, 0) is copied!A point (20, 0) is copied!Right bottom is (20, 0)A point (20, 0) is erased!A point (20, 0) is erased!A rectangle (10, 10) to (20, 0) is erased!A point (20, 0) is erased!A point (10, 10) is erased!

HINT

Append Code

append.cc,

#include <iostream> using namespace std; class Point { private: int x,y; public: Point() { x = 0; y = 0; } Point(int _x,int _y) { x = _x; y = _y; cout << "A point ("<<x<<", "<<y<<") is created!" << endl; } Point(const Point& k) { x = k.x; y = k.y; cout << "A point ("<<x<<", "<<y<<") is copied!" << endl; } int getX() { return x; } int getY() { return y; } friend ostream& operator << (ostream& os,const Point &k) { os << "("<<k.x<<", "<<k.y<<")"; return os; } ~Point() { cout << "A point ("<<x<<", "<<y<<") is erased!" << endl; } }; class Rectangle { private: Point leftTop,rightBottom; public: Rectangle(int _x1,int _y1,int _x2,int _y2):leftTop(_x1,_y1),rightBottom(_x2,_y2)//注意这里的构造方法 { cout << "A rectangle "<<leftTop<<" to "<<rightBottom<<" is created!" << endl; } Point& getLeftTop() { return leftTop; } Point getRightBottome() //一点一点试呗 { return rightBottom; } int getArea() { int ax = leftTop.getX() - rightBottom.getX(); int ay = leftTop.getY() - rightBottom.getY(); int area = ax * ay; return area > 0 ? area : -area; } ~Rectangle() { cout << "A rectangle "<<leftTop<<" to "<<rightBottom<<" is erased!" << endl; } }; int main() { int cases; int x1, y1, x2, y2; cin>>cases; for (int i = 0; i < cases; i++) { cin>>x1>>y1>>x2>>y2; Rectangle rect(x1,y1,x2,y2); cout<<"Area: "<<rect.getArea()<<endl; cout<<"Left top is ("<<rect.getLeftTop().getX()<<", "<<rect.getLeftTop().getY()<<")"<<endl; cout<<"Right bottom is ("<<rect.getRightBottome().getX()<<", "<<rect.getRightBottome().getY()<<")"<<endl; } return 0; }