verilog中for循环的转化使用

参考总结自Verilog那些事。。。 转摘自：http://blog.chinaaet.com/lincoding/p/5100050055

/* 单个for循环 */ ` for ( i=0; i<10; i++ )

{

Act++;

}

//1、时序实现

case ( i )

0: begin if ( x == C1 ) begin x <= x + 1'b1; Act <= Act + 1'b1; end if ( C1 == 10 - 1 ) begin x <= 8'd0; C1 <= 8'd0; i <= i + 1'b1; end else C1 <= C1 + 1'b1; end

endcase

//2、步骤实现

case ( i )

0: if ( x == 10 ) begin x <= 8'd0; i <= i + 1'b1; end else begin x <= x + 1'b1; Act <= Act + 1'b1; end

endcase

/* for循环嵌套 类型1 */

for ( x=0; x<10; x++ )

{

for ( y=0; y<10; y++ ) { Act++; }

}

//1、时序实现

case ( i )

0: begin if ( x == C1 ) begin x <= x + 1'b1; Act <= Act + 1'b1; end if ( C1 == 100-1 ) begin x <= 0; C1 <= 0; i <= i + 1'b1; end else C1 <= C1 + 1'b1; end

endcase

//2、步骤实现

case ( i )

0: if ( x == 100 ) begin x <= 8'd0; i <= i + 1'b1; end else begin x <= x + 1'b1; Act <= Act + 1'b1; end

endcase

/* for循环嵌套 类型2 */

for ( x=0; x<10; x++ )

{

for ( y=0; y<10; y++ ) { Act1++; Act2++; }

}

//1、时序实现

case ( i )

0: begin if ( x == C1 ) begin x <= x + 1'b1; Act1 <= Act1 + 1'b1; Act2 <= Act2 + 1'b1; end if ( C1 == 100-1 ) begin x <= 0; C1 <= 0; i <= i + 1'b1; end else C1 <= C1 + 1'b1; end

endcase

//2、步骤实现

case ( i )

0: if ( x == 100 ) begin x <= 8'd0; i <= i + 1'b1; end else begin x <= x + 1'b1; Act1 <= Act1 + 1'b1; Act2 <= Act2 + 1'b1; end

endcase

/* for循环嵌套 类型3 */

for ( x=0; x<10; x++ )

{

Act1++; for ( y=0; y<10; y++ ) { Act2++; }

}

//1、时序实现

case ( i )

0: begin if ( x == C1 ) begin x <= x + 8'd10; Act1 <= Act1 + 1'b1; end if ( y == C1 ) begin y <= y + 1'b1; Act2 <= Act2 + 1'b1; end if ( C1 == 100-1 ) begin x <= 0; y <= 0; C1 <= 0; i <= i + 1'b1; end else C1 <= C1 + 1'b1; end

endcase

//2、步骤实现

case ( i )

0: if ( x == 10 ) begin x <= 8'd0; y <= 8'd0; i <= i + 1'b1; end else if ( y == 10 ) begin x <= x + 1'b1; y <= 8'd0; Act1 <= Act1 + 1'b1; end else begin y <= y + 1'b1; Act2 <= Act2 + 1'b1; end

endcase

/* for循环嵌套 类型4 */

for ( x=0; x<10; x++ )

{

Act1++; for ( y=0; y<10; y++ ) { Act2 = Act1; }

}

//1、时序实现

case ( i )

0: begin if ( x == C1 ) begin x <= x + 8'd10; Act1 = Act1 + 1'b1; //使用阻塞赋值 end if ( y == C1 ) begin y <= y + 1'b1; Act2 <= Act1; end if ( C1 == 100-1 ) begin x <= 0; y <= 0; C1 <= 0; i <= i + 1'b1; end else C1 <= C1 + 1'b1; end

//2、步骤实现

case ( i )

0: if ( x == 10 ) begin x <= 8'd0; y <= 8'd0; i <= i + 1'b1; end else if ( y == 10 ) begin x <= x + 1'b1; y <= 8'd0; Act1 <= Act1 + 1'b1; end else begin y <= y + 1'b1; Act2 <= Act1; end

endcase

/* for循环嵌套 类型5 */

for ( x=0; x<10; x++ )

{

Act1 = Act2; for ( y=0; y<10; y++ ) { Act2++; }

}

//1、时序实现

case ( i )

0: begin if ( x == C1 ) begin x <= x + 8'd10; Act1 <= Act2; //使用阻塞赋值 end if ( y == C1 ) begin y <= y + 1'b1; Act2 = Act2 + 1'b1; end if ( C1 == 100-1 ) begin x <= 0; y <= 0; C1 <= 0; i <= i + 1'b1; end else C1 <= C1 + 1'b1; end

//2、步骤实现

case ( i )

0: if ( x == 10 ) begin x <= 8'd0; y <= 8'd0; i <= i + 1'b1; end else if ( y == 10 ) begin x <= x + 1'b1; y <= 8'd0; Act1 <= Act2; end else begin y <= y + 1'b1; Act2 <= Act2 + 1'b1; end

endcase

/* for循环嵌套 类型6，此法为类型4，5，6中最好的 */

for ( x=0; x<10; x++ )

{

Act2++; for ( y=0; y<10; y++ ) { Act1 = Act2; }

}

case ( i ) 0: begin if ( x == C1 ) begin x <= x + 8'd10; Act2 <= ( x != 101 - 1 ) ? Act2 + 1'b1 : Act2; end if ( y + 1 == C1 ) begin y <= y + 1'b1; Act1 <= Act2; end if ( C1 === 101 - 1 ) begin x <= 8'd0; y <= 8'd0; i <= i + 1'b1; end else C1 <= C1 + 1'b1; end endcase `