2649: 段位计算

xiaoxiao2021-02-28  114

2649: 段位计算

Time Limit: 1 Sec   Memory Limit: 128 MB Submit: 152   Solved: 94 [ Submit][ Status][ Web Board]

Description

输入分数score,根据以下信息输出段位

青铜:0<score<=1200              Brass

白银:1200<score<=1450        Silver

黄金:1450<score<=1700        Gold

白金:1700<score<=2000        Platinum gold

钻石:2000<score                   Diamonds

Input

输入一个分数

Output

输出对应段位

Sample Input

1000

Sample Output

Brass

AC代码:#include <stdio.h> #include <stdlib.h> int main() { int score; scanf("%d",&score); if(score>0&&score<=1200) printf("Brass\n"); if(score>1200&&score<=1450) printf("Silver\n"); if(score>1450&&score<=1700) printf("Glod\n"); if(score>1700&&score<=2000) printf("Platinum gold\n"); if(score>2000) printf("Diamonds\n"); return 0; }

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