PAT basic 1026

#include <iostream> using namespace std; int main() { int a, b; cin >> a >> b; int n = ((b - a) + 50) / 100; //由于要四舍五入 int hour = n / 3600; n = n % 3600; //只能从前往后取数 int minute = n / 60, second = n % 60; printf("d:d:d", hour, minute, second); return 0; }