还是A+B
时间限制：
1000 ms | 内存限制：
65535 KB
难度：
1
描述
输入两个小于100的正整数A和B，输出A+B；
A，B均为每位数字对应的英文字母，结果为十进制数。
输入
A，B。
输出
A+B；
样例输入
one + two =
one + two zero =
样例输出
3
21
import java.util.Scanner;
public class Main {
public static int judge(String str) {
String num[] = { "zero", "one", "two", "three", "four", "five", "six",
"seven", "eight", "nine" };
for (int i = 0; i < num.length; i++) {
if (str.equals(num[i])) {
return i;
}
}
return -1;
}
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
while (scanner.hasNext()) {
int numone = 0, numtwo = 0;
String string = scanner.next();
while (judge(string) != -1) {
numone = numone * 10 + judge(string);
string = scanner.next();
}
string = scanner.next();
while (judge(string) != -1) {
numtwo = numtwo * 10 + judge(string);
string = scanner.next();
}
System.out.println(numone + numtwo);
}
}
}
