非递归方法后序遍历二叉树

xiaoxiao2021-02-28  101

typedef char BTreeData;

// 二叉树的结点

typedef struct _btreeNode

{

BTreeData data;

struct _btreeNode *lchild;   // 指向左孩子结点的指针

struct _btreeNode *rchild;   // 指向右孩子结点的指针

}BTreeNode;

 

// 二叉树

typedef struct _btree

{

BTreeNode *root;     // 指向二叉树的根节点

int  count;          // 记录二叉树结点的个数

}BTree;

 

BTree *Create_BTree()

{

BTree *btree = (BTree*)malloc(sizeof(BTree)/sizeof(char));

if (btree == NULL)

return NULL;

btree->count = 0;

btree->root  = NULL;

return btree;

}

 

 

//非递归后序遍历

void last2_order (BTreeNode *node)

{

if (node == NULL)

{

errno = ERROR;

return;

}

LinkStack *Stack = Create_Stack ();

BTreeNode *tmp = node;   //指向当前节点

BTreeNode *pre = NULL;  //指向被输出的节点

Push (Stack,tmp);

while (StackEmpty (Stack) != TRUE)

{

GetTop (Stack,&tmp);

//P不存在左孩子和右孩子,或者P存在左孩子或右孩子,但左右孩子已经被输出

if(tmp->lchild == NULL && tmp->rchild == NULL

|| pre != NULL &&(tmp->lchild == pre || tmp->rchild == pre))

{

Pop (Stack,&tmp);

printf("L",tmp->data);

pre = tmp;//指向被输出的节点

continue;

}

if(tmp->rchild)

{

Push (Stack,tmp->rchild);

}

if(tmp->lchild)

{

Push (Stack,tmp->lchild);

}

}

}

 

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