题目:请编写一个c函数,该函数给出一个字节中被置为1的位的个数
#include <stdio.h>
int func1(char n)
{
int count = 0;
int i;
for (i = 0; i < 8; i++)
{
if (n&1 == 1)
count++;
n = n >> 1;
}
return count;
}
方法一：int main(){char n = 9;int res = func1(n);printf ("%d\n",res);return 0;}union A{int b;char
ch;};
方法二：
int main()
{
union A a;
a.b = 9;
int res = func2(a.ch);
printf ("%d\n",res);
return 0;
}
方法三：
int main()
{
int n = 9;
int ch;
int *p = &n;
char *pch = (char *)p;
int res = func3(*pch);
printf ("%d\n",res);
return 0;
}
