561. Array Partition I

xiaoxiao2021-02-28  110

题目来源【Leetcode】

Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), …, (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible.

Example 1: Input: [1,4,3,2]

Output: 4 Explanation: n is 2, and the maximum sum of pairs is 4 = min(1, 2) + min(3, 4). Note: n is a positive integer, which is in the range of [1, 10000]. All the integers in the array will be in the range of [-10000, 10000].

这道题很简单,直接放代码

class Solution { public: int arrayPairSum(vector<int>& nums) { int s = nums.size(); if(s == 0)return 0; sort(nums.begin(),nums.end()); int sum = 0; for(int i = 0; i < s; i = i+2){ sum += nums[i]; } return sum; } };
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