[leetcode 237]Delete Node in a Linked List

xiaoxiao2021-02-28  97

# Definition for singly-linked list. # class ListNode(object): #     def __init__(self, x): #         self.val = x #         self.next = None class Solution(object):     def deleteNode(self, node):         """         :type node: ListNode         :rtype: void Do not return anything, modify node in-place instead.         """         node.val=node.next.val

        node.next=node.next.next

把下一个节点的值拿来,删除下一个节点

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