2016-11-01 回答的一个百度知道的问题,现把答案改进如下:
#!usr/bin/env python3 import re def COUNTT(A,B,C): return (A[0]*B[1]*C[2] + B[0]*C[1]*A[2] + C[0]*A[1]*B[2] -C[0]*B[1]*A[2] - B[0]*A[1]*C[2] - A[0]*C[1]*B[2]) def main(): M, N, P, Q = [[0]*3 for _ in range(4)] for i in range(3): msg = '请依次输入第{}个方程的x,y,z的系数以及常数项(以空格隔开): ' while True: nums = re.split(r'\s+', input(msg.format(i+1)).strip()) try: M[i], N[i], P[i], Q[i] = [float(n) for n in nums] except ValueError: print('输入有误, 请重新输入!') else: break D = COUNTT(M, N, P) if D == 0 : print('根不存在或者有无穷多个根!') else: print('x =', COUNTT(Q, N, P)/D) print('y =', COUNTT(M, Q, P)/D) print('z =', COUNTT(M, N, Q)/D) if __name__ == '__main__': main()
问题链接: https://zhidao.baidu.com/question/922925054387169299
