一段基于jQuery的,验证用户密码的简单应用

xiaoxiao2026-09-03  2

<html> <head> <title>PASSWORD CHECK</title> <script language="javascript" type="text/javascript" src="../jquery/jquery.js"></script> <script language="javascript" type="text/javascript"> $(document).ready(function(){  initP(); }); // check the result generally var ip = new RegExp(/[0]+|111|121/); // message for notice var msgMap = { "^0":"original password is wrong", "^11|^12":"new password is too simple", "^10":"new password is too short", "^19":"new password is too long", "130":"repeat password is wrong" }; // find the input text var pMap = { "^0":"pw0", "^11|^12":"pw1", "^10":"pw1", "^19":"pw1", "130":"pw2" }; // initiate function initP(){ $("input[type='submit']").click(function(){   return sC();//submit check  });  iC();//input check } //check for submit function sC(){   var ps = getApw();    var r = aop(ps[0].value)+""+anp(ps[1].value)+""+arp(ps[1].value,ps[2].value);    if (r.match(ip))    {     for(var k in msgMap){      if (r.match(k))      {       alert(msgMap[k]);       try       {$("#"+pMap[k]).select();}       catch (e)       {}       return false;      }     }    } } // get all password function getApw(){  var ps = new Array();    $("input[id^='pw']").each(function(e){     var i = this.id.replace('pw','');     ps[i] = this;    });  return ps; } // check for input function iC(){   var n = document.createElement("span");//create the element for notice  $("input[id^='pw']").keyup(function(){   var ps = getApw();   var r = aop(ps[0].value)+""+anp(ps[1].value)+""+arp(ps[1].value,ps[2].value);   if (r.match(ip))    {     for(var k in msgMap){      if (r.match(k))      {       n.innerText = msgMap[k];       $("#"+pMap[k]).after(n);// display the notice      }     }    }   else n.innerText = "";  }); } // check the new password function anp(p){  if (p.length < 8) return 0;// it is too short  if (p.length > 16) return 9;// it is too long  var ls = 0;  if (p.match(/([0-9])+/)) {ls++;}  if (p.match(/([a-z])+/)) {ls++;}  if (p.match(/([A-Z])+/)) {ls++;}  if (p.match(/([^0-9a-zA-Z])+/)) {ls++;}  if (ls >= 3) return 3;// it is ok  return ls;//it is too simple } // check the repeat password function arp(np,rp){  if (np == rp) return 1;  else return 0; } // check the original password function aop(p){  var op = 1;  if (p == op) return 1;  else return 0; } // clean all password input text function clean(){  var ps = getApw();  for (var i = 0;i < ps.length ;i++ )  {   ps[i].value="";  } } </script> </head> <body> DEMO: <br> <form id="pw"> ORIGINAL PASSWORD:<input type="text"  id="pw0"/> <br><br> NEW PASSWORD:<input type="text"  id="pw1"/> <br><br> REPEAT PASSWORD:<input type="text" id="pw2"/> <br><br> <input type="submit" value="submit"/> </form> </body> </html>

     我想根据html的内容基本能明白id和输入的对应关系,我是根据对原有密码,新密码和重复密码的验证结果集合成一个结果进行统一的验证,并不是分开校验,所以可能对理解代码有一点儿障碍,当然这么写也是存在实验性的了,恩,能力非常非常有限,还希望各位同学给予批评和指正,在下感激万分。

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