Oracle中的树状展示与储存

xiaoxiao2026-08-30  18

[size=medium]树状结构的存储与展示: drop table article; create table article ( id number primary key, cont varchar2(4000), pid number, isleaf number(1), --0代表非叶子节点,1代表叶子节点 alevel number(2) ); insert into article values(1,'蚂蚁大战大象',0,0,0); insert into article values(2,'大象被打趴下了',1,0,1); insert into article values(3,'蚂蚁也不好过',2,1,2); insert into article values(4,'瞎说',2,0,2); insert into article values(5,'没有瞎说',4,1,3); insert into article values(6,'怎么可能',1,0,1); insert into article values(7,'怎么没有可能',6,1,2); insert into article values(8,'可能性很大',6,1,2); insert into article values(9,'大象进医院了',2,0,2); insert into article values(10,'护士是蚂蚁',9,1,3); cmmmit; 展示树状展示: create or replace procedure p (v_pid article.pid%type,v_level binary_integer) is cursor c is select * from article where pid = v_pid; v_preStr varchar2(1024) :='';begin for i in 1..v_level loop v_preStr :=v_preStr ||'----'; end loop; for v_article in c loop dbms_output.put_line(v_preStr || v_article.cont); if(v_article.isleaf = 0) then p(v_article.id,v_level+1); end if; end loop;end; 显示出错的信息:show error; set serveroutput on; 调用存储:exec p(0,0); SQL> exec p(0,0); 蚂蚁大战大象 ----大象被打趴下了 --------蚂蚁也不好过 --------瞎说 ------------没有瞎说 --------大象进医院了 ------------护士是蚂蚁 ----怎么可能 --------怎么没有可能 --------可能性很大 PL/SQL 过程已成功完成。
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