n+1问题:在默认情况下,使用query.iterator()查询,有可能有n+1问题,所谓n+1是指在查询对象的时候发出n+1条查询语句。
1:先发出查询id列表的sql语句。
N:再发出根据id到缓存中查询,如果缓存中有与之匹配的数据,就从缓存中取得数据,否则依次根据id发出sql语句。
list和iterator到区别:
list:在默认情况下,list每次都会发出sql查询实体对象,list会向缓存里放数据,但是不会利用缓存中的数据。
iterator:首先发出一条查询id列表的sql语句,如果缓存中有与之匹配的数据,就从缓存中取得数据,否则依次根据id发出sql语句。
import java.util.Iterator;import java.util.List;import junit.framework.TestCase;import org.hibernate.Session;import org.hibernate.Transaction;//...public class QueryTest extends TestCase { public void testQuery1() { Session session = null; Transaction t = null; try { session = HibernateUtils.getSession(); t = session.beginTransaction(); /** * 采用list查询,将发出一条sql语句来获取student数据 * Hibernate: select student0_.id as id1_, student0_.name as name1_ from Student student0_ 张三 李四 */ List<Student> list = session.createQuery("from Student").list(); for (Iterator<Student> iter = list.iterator(); iter.hasNext();) { Student student = iter.next(); System.out.println(student.getName()); } t.commit(); } catch (Exception e) { e.printStackTrace(); t.rollback(); } finally { HibernateUtils.closeSession(session); } } public void testQuery2() { Session session = null; Transaction t = null; try { session = HibernateUtils.getSession(); t = session.beginTransaction(); /** * N+1问题: * 使用iterator,先发出查询id列表的sql语句, * Hibernate: select student0_.id as col_0_0_ from Student student0_ * 再发出根据id查询实体对象的sql * Hibernate: select student0_.id as id1_0_, student0_.name as name1_0_ from Student student0_ where student0_.id=? 张三 Hibernate: select student0_.id as id1_0_, student0_.name as name1_0_ from Student student0_ where student0_.id=? 李四 × */ Iterator<Student> it = session.createQuery("from Student").iterate(); while(it.hasNext()){ Student student = it.next(); System.out.println(student.getName()); } t.commit(); } catch (Exception e) { e.printStackTrace(); t.rollback(); } finally { HibernateUtils.closeSession(session); } } public void testQuery3() { Session session = null; Transaction t = null; try { session = HibernateUtils.getSession(); t = session.beginTransaction(); List<Student> list = session.createQuery("from Student").list(); for (Iterator<Student> iter = list.iterator(); iter.hasNext();) { Student student = iter.next(); System.out.println(student.getName()); } System.out.println("======================="); /** * 不会出现n+1问题 * 因为list操作已经将对象加入到一级缓存,所以在使用iterator的时候, * 他首先发出查询id列表的sql,再根据id到缓存中获取数据, * 只有在缓存中找不到,才再次发出sql语句Hibernate: select student0_.id as id1_, student0_.name as name1_ from Student student0_张三李四=======================Hibernate: select student0_.id as col_0_0_ from Student student0_张三李四 */ Iterator<Student> it = session.createQuery("from Student").iterate(); while(it.hasNext()){ Student student = it.next(); System.out.println(student.getName()); } t.commit(); } catch (Exception e) { e.printStackTrace(); t.rollback(); } finally { HibernateUtils.closeSession(session); } }}