Python Challenge (level 4)

xiaoxiao2026-08-18  24

URI: [url]http://www.pythonchallenge.com/pc/def/linkedlist.html[/url] 说明: 按提示将linkedlist.html改成likedlist.php进入level 4 从title和图片可以看出来这题就像打水井一样,需要一遍又一遍的机械进行才能获得答案。 page source显示图片的href 后面有一个nothing=12345的调用 urllib may help. DON'T TRY ALL NOTHINGS, since it will never end. 400 times is more than enough. 调用linkedlist.php?nothing=12345得到了and the next nothing is 92512 从中得到规律,根据每次获得的nothing值来进行下次url访问。 解题方法: #!/usr/bin/env pythonimport reimport urlliburl="http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing="nothing = "12345"search = re.compile(" (\d*)$")search_html = re.compile("\.html$")for i in xrange(300): print "%s: " % nothing, line = urllib.urlopen( "%s%s" % (url,nothing) ).read() print line # handle the solution (last) line if search_html.findall (line): break match = search.findall (line) if match: # next nothing nothing = match [0] else: # handle the divide by two line nothing = str (int (nothing) / 2 ) 过关答案: peak 相关资源:pythonchallenge level2官方方法集
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