一道sql试题——据说是盛大的

xiaoxiao2026-08-12  36

表结构:id name subject score createdate 建表语句: Code SET ANSI_NULLS ON GO SET QUOTED_IDENTIFIER ON GO CREATE TABLE [dbo].[Score]( [id] [bigint] IDENTITY(1,1) NOT NULL, [name] [nvarchar](50) CONSTRAINT [DF_Score_name] DEFAULT (''), [subject] [nvarchar](50) CONSTRAINT [DF_Score_subject] DEFAULT (''), [score] [float] NOT NULL CONSTRAINT [DF_Score_score] DEFAULT ((0)), [createdate] [datetime] NOT NULL ) ON [PRIMARY] 向表预赛几条数据: Code insert into Score select '1','Ivan.Mao','English','40','2/25/2009 8:13:42.000' union select '2','name8','English','80','2/25/2009 8:13:42.000' union select '3','Ivan.Mao','Math','80','2/22/2009 8:13:42.000' union select '4','Ivan.Mao','YuWen','58','2/22/2009 12:00:00.000' union select '5','name8','Math','80','2/21/2009 11:59:59.000' union select '7','Ivan.Mao','DiLi','33','2/21/2009 11:59:59.000' union select '8','name1','subject1','80','2/21/2009 11:59:59.000' union select '9','name2','subject1','80','2/21/2009 11:59:59.000' union select '10','name3','subject1','80','2/21/2009 11:59:59.000' union select '11','name4','subject1','90','2/21/2009 11:59:59.000' union select '12','name5','subject1','100','2/21/2009 11:59:59.000' union select '13','name6','subject1','50','2/21/2009 11:59:59.000' union select '14','name7','subject1','95','2/21/2009 11:59:59.000' 1. 创建时间为3天前0点创建的纪录,20分钟前创建的纪录? select * from Score where DATEDIFF(d,createdate,GETDATE())>3 select * from Score where DATEDIFF(n,createdate,GETDATE())>20 2. 3门以上不及格学生的学生姓名? select [name] from Score where score<60 group by [name] having COUNT(*)>=3 3. id name 1 a 2 b 3 a 4 a id为identity,只留一条a与一条b --select * into Score_Test3 from Score select * from Score select * from Score_Test3 delete from Score_Test3 where id not in ( select max(id) from Score_Test3 group by [name] ) 4. 总分排名5-7的学生姓名(name,score),最好写成存储过程,请注意并列排名的问题 --select * into Score_Test4 from Score select * from Score select * from Score_Test4 select top 3 t2.* from (select top 7 [name],sum(score) as totalScore from Score_Test4 group by [name] order by sum(score)) t2 order by t2.totalScore 没有考虑并列排名问题,还待斟酌。。。[/color][/size] 相关资源:敏捷开发V1.0.pptx
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