1.栈的简单应用:数制转换问题(将十进制数N转换为r进制的数) 将十进制数N转换为r进制的数 Change.java
import java.util.Scanner; import java.util.Stack; public class Change { Stack<String> stack = new Stack<String>(); //num是想要转换的数字,rank是想要转换的进制 public int getResult(int num,int rank) {//获取整数商 return num/rank; } public int getRemain(int num,int rank) {//获取余数 return num%rank; } public void run(int num,int rank) { int result=getResult(num, rank); //当整除是将余数添加到栈中,退出递归进程 if(result==0) { stack.push(getRemain(num, rank)+" "); }else { stack.push(getRemain(num, rank)+" "); run(result, rank);//进行递归 } } public static void main(String[] args) { Change change=new Change(); System.out.println("请输入一个十进制数字:"); Scanner sca = new Scanner(System.in); int num = sca.nextInt(); System.out.println("请输入想要转换为几进制的数字:"); int rank = sca.nextInt(); change.run(num, rank); String Result = ""; while(!change.stack.isEmpty()) { Result += change.stack.pop(); } System.out.println(Result); } }