Neo4j 做推荐 (7)—— 基于内容的相似度量标准

xiaoxiao2025-05-02  18

相似度量是用于生成个性化推荐的重要件,些推荐允量化两个目的相似程度(或者我稍后会看到,两个用偏好的相似程度)。

Jaccard指数是01之间的数字,表示两组的相似程度。

两个相同集合的Jaccard指数是1.如果两个集合没有公共元素,则Jaccard索引为0.通过将两个集合的交集的大小除以两个集合的并集来计算Jaccard

我们可以计算电影类型集的Jaccard指数,以确定两部电影的相似程度。

哪些电影是跟《盗梦空间》基于Jaccard指数最相似的?

MATCH (m:Movie {title: "Inception"})-[:IN_GENRE]->(g:Genre)<-[:IN_GENRE]-(other:Movie) WITH m, other, COUNT(g) AS intersection, COLLECT(g.name) AS i MATCH (m)-[:IN_GENRE]->(mg:Genre) WITH m,other, intersection,i, COLLECT(mg.name) AS s1 MATCH (other)-[:IN_GENRE]->(og:Genre) WITH m,other,intersection,i, s1, COLLECT(og.name) AS s2 WITH m,other,intersection,s1,s2 WITH m,other,intersection,s1+filter(x IN s2 WHERE NOT x IN s1) AS union, s1, s2 RETURN m.title, other.title, s1,s2,((1.0*intersection)/SIZE(union)) AS jaccard ORDER BY jaccard DESC LIMIT 100

分析:

1. 首先查询出电影盗梦空间和与它流派相关性的电影集other

2. count(g) 其实就是电影盗梦空间和电影集other 的流派交集的数量(共同的流派)

3. s1+filter(x IN s2 WHERE NOT x IN s1) AS union  此 union 即是s1 和 s2 的并集(集合s1 加上 s2中不包含s1 的那部分)

4. ((1.0*intersection)/SIZE(union)) AS jaccard  根据上面的Jaccard指数公式计算所得的指数。

运行结果如下:

 

我们可以将这个相同的方法应用于电影的所有特征(如流派、演员、导演等):

MATCH (m:Movie {title: "Inception"})-[:IN_GENRE|:ACTED_IN|:DIRECTED]-(t)<-[:IN_GENRE|:ACTED_IN|:DIRECTED]-(other:Movie) WITH m, other, COUNT(t) AS intersection, COLLECT(t.name) AS i MATCH (m)-[:IN_GENRE|:ACTED_IN|:DIRECTED]-(mt) WITH m,other, intersection,i, COLLECT(mt.name) AS s1 MATCH (other)-[:IN_GENRE|:ACTED_IN|:DIRECTED]-(ot) WITH m,other,intersection,i, s1, COLLECT(ot.name) AS s2 WITH m,other,intersection,s1,s2 WITH m,other,intersection,s1+filter(x IN s2 WHERE NOT x IN s1) AS union, s1, s2 RETURN m.title, other.title, s1,s2,((1.0*intersection)/SIZE(union)) AS jaccard ORDER BY jaccard DESC LIMIT 100

 

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