使用ajaxfileupload.js实现ajax异步上传

xiaoxiao2021-02-28  58

1.下载异步上传的js文件 ajaxfileupload.js 2.页面引入js文件 <script type="text/javascript" src="<%=request.getContextPath()%>/static/js/ajaxfileupload.js"></script> 3.具体方法 function mnUpload(){ $.ajaxFileUpload({ url:'/seeyon/letter.do?method=letterUpload', secureuri:false, fileElementId:'file',//file标签的id dataType: 'json',//返回数据的类型 success: function (data, status) { $(“#filed”).val(data.fileId); $("#fileNameStep").text(data.fileName); }, error: function (data, status, e) { } }); } 4.html文件内容 <span class="form_td"><span class="form_title">上传公函:</span></span> <span class="form_td" id="files"> <input type="file" id="file" name="file" οnchange="mnUpload()"/> <span id="fileNameStep">${file.name}</span> <input type="hidden" name="fileId" id="fileId" value="${file.id}"/> </span> 5.后台java文件接受上传文件的方法 public void letterUpload(HttpServletRequest request, HttpServletResponse response) throws Exception{ response.setCharacterEncoding("UTF-8"); response.setContentType("text/html;charset=GB2312"); SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm"); SimpleDateFormat sdff = new SimpleDateFormat("yyyy-MM-dd"); String filePaths = "letter/"+sdff.format(new Date())+"/"; try { Upload upload = new Upload(); Map<String,Object> map = upload.uploadFile(request, filePaths); MultipartFile file = (MultipartFile) map.get("file"); KdFile kdFile = new KdFile(); kdFile.setId((Long) map.get("id")); kdFile.setName(file.getOriginalFilename()); kdFile.setType(String.valueOf(map.get("fileType"))); kdFile.setPath(String.valueOf(map.get("path"))); kdFile.setSize(String.valueOf(file.getSize())); kdFile.setReName((Long) map.get("id")); Date date = new Date(); sdf.format(date); kdFile.setTime(date); //新增上传数据到数据库上传表 kdFileManager.add(kdFile); JSONObject ss=new JSONObject(); //新建json对象 Long fileId=(Long) map.get("id"); ss.put("fileId",fileId.toString()); ss.put("fileName",kdFile.getName()); response.getWriter().print(ss); } catch (IllegalStateException e) { logger.error("获取request异常"); e.printStackTrace(); } catch (IOException e) { logger.error("上传文件异常"); e.printStackTrace(); } }
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