LeetCode 561 Array Partition I(数组划分)

xiaoxiao2021-02-28  76

翻译

原文

Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), …, (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible.

Example 1: Input: [1,4,3,2]

Output: 4 Explanation: n is 2, and the maximum sum of pairs is 4. Note: n is a positive integer, which is in the range of [1, 10000]. All the integers in the array will be in the range of [-10000, 10000].

代码

public int arrayPairSum(int[] nums) { Arrays.sort(nums); int sum = 0; for (int i = 0; i < nums.length; i+=2) { sum += nums[i]; } return sum; }
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