一,算法代码
#include<stdio.h>
struct sjf {
char name[
10];
float arrivetime;
float servicetime;
float starttime;
float finishtime;
float zztime;
float dqzztime;
};
struct sjf b[
100];
void Sinput(
struct sjf *p,
int N) {
int i;
printf(
"输入进程的名称、到达时间、服务时间:(例如 : x 0 100)\n");
for(i=
0; i<=N-
1; i++) {
printf(
"输入第%d进程的名称、到达时间、服务时间:",i+
1);
scanf(
"%s%f%f",&p[i].name,&p[i].arrivetime,&p[i].servicetime);
}
}
void SPrint(
struct sjf *p,
float arrivetime,
float servicetime,
float starttime,
float finishtime,
float zztime,
float dqzztime,
int N)
{
int k;
printf(
"\n执行顺序:\n");
printf(
"%s",p[
0].name);
for(k=
1; k<N; k++) {
printf(
"-%s",p[k].name);
}
printf(
"\n进程名\tarrive\tservice\tstart\tfinish\tzhouzhuan\tdaiquanzz\n");
for(k=
0; k<=N-
1; k++) {
printf(
"%s\t%-.2f\t%-.2f\t%-.2f\t%-.2f\t%-.2f\t%-.2f\t\n\n",
p[k].name,p[k].arrivetime,p[k].servicetime,p[k].starttime,p[k].finishtime,
p[k].zztime,p[k].dqzztime);
}
printf(
"\n");
}
void Ssort(
struct sjf *p,
int N)
{
int i,j;
for( i=
1; i<=N-
1; i++)
for( j=
1; j<=i; j++)
if(p[i].servicetime<p[j].servicetime) {
struct sjf temp;
temp=p[i];
p[i]=p[j];
p[j]=temp;
}
}
void Sdeal(
struct sjf *p,
float arrivetime,
float servicetime,
float starttime,
float finishtime,
float zztime,
float dqzztime,
int N)
{
int k;
for(k=
0; k<=N-
1; k++) {
if(k==
0) {
p[k].starttime=p[k].arrivetime;
p[k].finishtime=p[k].arrivetime+p[k].servicetime;
}
else {
p[k].starttime=p[k-
1].finishtime;
p[k].finishtime=p[k-
1].finishtime+p[k].servicetime;
}
}
for(k=
0; k<=N-
1; k++) {
p[k].zztime=p[k].finishtime-p[k].arrivetime;
p[k].dqzztime=p[k].zztime/p[k].servicetime;
}
}
void SJF(
struct sjf *p,
int N)
{
float arrivetime=
0,servicetime=
0,starttime=
0,
finishtime=
0,zztime=
0,dqzztime=
0;
Ssort(p,N);
Sdeal(p,arrivetime,servicetime,starttime,finishtime,zztime,dqzztime,N);
SPrint(p,arrivetime,servicetime,starttime,finishtime,zztime,dqzztime,N);
}
void main() {
int M;
printf(
"-----------短作业优先调度算法-----------\n");
printf(
"输入进程数:");
scanf(
"%d",&M);
Sinput(b,M);
SJF(b,M);
}
二,算法截图
本算法转自:https://wenku.baidu.com/view/c38baaf3fad6195f302ba668.html