Given A, B, and n, you are to calculate the value of f(n).
Input The input consists of multiple test cases. Each test case contains 3 integers A, B and n on a single line (1 <= A, B <= 1000, 1 <= n <= 100,000,000). Three zeros signal the end of input and this test case is not to be processed. Output For each test case, print the value of f(n) on a single line. Sample Input 1 1 3 1 2 10 0 0 0 Sample Output 2 5 #include<stdio.h> int main() { int f[50],a,b,n,i; while(scanf("%d%d%d",&a,&b,&n)!=EOF) { if(a==0&&b==0&&n==0) break; f[1]=f[2]=1; for(i=3;i<=49;i++) f[i]=(a*f[i-1]+b*f[i-2])%7; printf("%d\n",f[nI]); } return 0; }
