[PAT-甲级]1031.Hello World for U

xiaoxiao2021-02-28  151

1031. Hello World for U (20)

时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue

Given any string of N (>=5) characters, you are asked to form the characters into the shape of U. For example, "helloworld" can be printed as:

h d e l l r lowo That is, the characters must be printed in the original order, starting top-down from the left vertical line with n 1 characters, then left to right along the bottom line with n 2 characters, and finally bottom-up along the vertical line with n 3 characters. And more, we would like U to be as squared as possible -- that is, it must be satisfied that n 1 = n 3 = max { k| k <= n 2 for all 3 <= n 2 <= N } with n 1 + n 2 + n 3 - 2 = N.

Input Specification:

Each input file contains one test case. Each case contains one string with no less than 5 and no more than 80 characters in a line. The string contains no white space.

Output Specification:

For each test case, print the input string in the shape of U as specified in the description.

Sample Input: helloworld! Sample Output: h ! e d l l lowor

解题思路:左边的长度和右边的长度都为(n+2)/3, 中间的长度为n + 2 - (n+2)/3 - (n+2)/3

代码如下:

#include<stdio.h> #include<cstring> int main() { char str[100]; gets(str); int n = strlen(str); int n1 = (n + 2) / 3, n3 = n1, n2 = n + 2 - n1 - n3; for (int i = 0; i < n1 - 1; i++) { printf("%c", str[i]); for (int j = 0; j < n2 - 2; j++) printf(" "); printf("%c\n", str[n - i - 1]); } for (int i = 0; i < n2; i++) printf("%c", str[n1 + i - 1]); return 0; }

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