Reverse digits of an integer.
Example1: x = 123, return 321 Example2: x = -123, return -321
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Note: The input is assumed to be a 32-bit signed integer. Your function should return 0 when the reversed integer overflows.
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问题描述：将一个整数进行翻转。注：整数是32位的有符号整数，当翻转的整数溢出时返回0。
分析：无论正负整数都可以一样处理进行reverse，但要注意溢出处理。
public class Solution {
public int reverse(int x) {
long result=0;
int a=0;
while(x!=0){
a=x;
result=result*10+a;
x=x/10;
if(result<Integer.MIN_VALUE || result>Integer.MAX_VALUE) //判断是否溢出
return 0;
}
return (int)result;
}
}
