We have two special characters. The first character can be represented by one bit 0. The second character can be represented by two bits (10 or 11).

Now given a string represented by several bits. Return whether the last character must be a one-bit character or not. The given string will always end with a zero.

Example 1:

Input: bits = [1, 0, 0] Output: True Explanation: The only way to decode it is two-bit character and one-bit character. So the last character is one-bit character.Example 2:

Input: bits = [1, 1, 1, 0] Output: False Explanation: The only way to decode it is two-bit character and two-bit character. So the last character is NOT one-bit character.Note:

1 <= len(bits) <= 1000. bits[i] is always 0 or 1.func isOneBitCharacter(bits []int) bool { i:= len(bits)-2 for ;i>=0 && bits[i]>0;{ i-- } return (len(bits)-i)%2 == 0 }

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