B - Unrequited Love ZOJ - 3601
There are n single boys and m single girls. Each of them may love none, one or several of other people unrequitedly and one-sidedly. For the coming q days, each night some of them will come together to hold a single party. In the party, if someone loves all the others, but is not loved by anyone, then he/she is called king/queen of unrequited love.
InputThere are multiple test cases. The first line of the input is an integer T ≈ 50 indicating the number of test cases.
Each test case starts with three positive integers no more than 30000 -- n m q. Then each of the next n lines describes a boy, and each of the next m lines describes a girl. Each line consists of the name, the number of unrequitedly loved people, and the list of these people's names. Each of the last q lines describes a single party. It consists of the number of people who attend this party and their names. All people have different names whose lengths are no more than 20. But there are no restrictions that all of them are heterosexuals.
<h4< dd=""> OutputFor each query, print the number of kings/queens of unrequited love, followed by their names in lexicographical order, separated by a space. Print an empty line after each test case. See sample for more details.
Sample Input 2 2 1 4 BoyA 1 GirlC BoyB 1 GirlC GirlC 1 BoyA 2 BoyA BoyB 2 BoyA GirlC 2 BoyB GirlC 3 BoyA BoyB GirlC 2 2 2 H 2 O S He 0 O 1 H S 1 H 3 H O S 4 H He O S Sample Output 0 0 1 BoyB 0 0 0 AC代码： #include<iostream> #include<cstdio> #include<string> #include<cstring> #include<algorithm> #include<cmath> #include<queue> #include<vector> #include<set> #include<stack> #include<map> #include<climits> using namespace std; const int maxn=30090; map<string,int> mp; set<int> s[maxn]; int sum,n,m,q,t; string x[maxn]; int get(string ch) { if(!mp.count(ch)) mp[ch]=sum++; return mp[ch]; } int main() { scanf("%d",&t); int i,j; while(t--) { scanf("%d%d%d",&n,&m,&q); mp.clear();//清零 for(i=0;i<maxn;i++) s[i].clear();//清零 string ch; int a,k; sum=0; for(i=0;i<n+m;i++) { cin>>ch>>a; k=get(ch); for(j=0;j<a;j++) { cin>>ch; s[k].insert(get(ch)); } } while(q--) { int o; scanf("%d",&o); for(i=0;i<o;i++) cin>>x[i]; string p=x[0]; k=0; for(i=1;i<o;i++) { if(!s[get(x[k])].count(get(x[i]))||s[get(x[i])].count(get(x[k]))) { k=i; p=x[i]; } } for(i=0;i<k;i++) { if(!s[get(x[k])].count(get(x[i]))||s[get(x[i])].count(get(x[k]))) { p=" "; break; } } if(p==" ") printf("0\n"); else cout<<1<<" "<<p<<endl; } printf("\n"); } return 0; }