今天把项目前端的身份证号码从最初的只是校验长度改为只允许正规的号码，具体内容如下
功能主要校验 年月日 地址 格式 以及最后一位的校验
var code="123132132121" var city={11:"北京",12:"天津",13:"河北",14:"山西",15:"内蒙古",21:"辽宁",22:"吉林",23:"黑龙江 ",31:"上海",32:"江苏",33:"浙江",34:"安徽",35:"福建",36:"江西",37:"山东",41:"河南",42:"湖北 ",43:"湖南",44:"广东",45:"广西",46:"海南",50:"重庆",51:"四川",52:"贵州",53:"云南",54:"西藏 ",61:"陕西",62:"甘肃",63:"青海",64:"宁夏",65:"新疆",71:"台湾",81:"香港",82:"澳门",91:"国外 "}; var tip = ""; var pass= true; var year = code.substr(6,4); var mounth = code.substr(10,2); var day = code.substr(12,2); if(!code || !/^\d{6}(18|19|20)?\d{2}(0[1-9]|1[12])(0[1-9]|[12]\d|3[01])\d{3}(\d|X)$/i.test(code)){ tip = "身份证号格式错误"; pass = false; } else if(!city[UUserCard.substr(0,2)]){ tip = "地址编码错误"; pass = false; } if(((year@0==0)||year0!=0)&&year%4==0){ if(mounth=='02'){ if(day*1>29){ pass = false; } } }else{ if(mounth=='02'){ if(day*1>28){ pass = false; } } } //18位身份证需要验证最后一位校验位 if(UUserCard.length == 18){ code = UUserCard.split(''); //∑(ai×Wi)(mod 11) //加权因子 var factor = [ 7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2 ]; //校验位 var parity = [ 1, 0, 'X', 9, 8, 7, 6, 5, 4, 3, 2 ]; var sum = 0; var ai = 0; var wi = 0; for (var i = 0; i < 17; i++) { ai = code[i]; wi = factor[i]; sum += ai * wi; } var last = parity[sum % 11]; if(parity[sum % 11] != code[17]){ tip = "校验位错误"; pass =false; } } if(!pass){ //校验失败 填写你要做的内容 }; 以上为主要代码，具体还要看你用什么方式实现
