spring

xiaoxiao2021-02-28  122

由jar变成war

<packaging>jar</packaging> 1 1

如果是上面的打包方式,启动方式则为

mvn package java -jar target/mymodule-0.0.1-SNAPSHOT.jar 12 12

改变成war

<?xml version="1.0" encoding="UTF-8"?> <project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd"> <!-- ... --> <packaging>war</packaging> <!-- ... --> <dependencies> <dependency> <groupId>org.springframework.boot</groupId> <artifactId>spring-boot-starter-web</artifactId> </dependency> <dependency> <groupId>org.springframework.boot</groupId> <artifactId>spring-boot-starter-tomcat</artifactId> <scope>provided</scope> </dependency> <!-- ... --> </dependencies> </project> 12345678910111213141516171819 12345678910111213141516171819

只需要把tomcat的范围改成provided

如果要发布到外部的tomcat同时需要改变启动方式

新增ServletInitializer类

import org.springframework.boot.builder.SpringApplicationBuilder; import org.springframework.boot.context.web.SpringBootServletInitializer; public class ServletInitializer extends SpringBootServletInitializer { @Override protected SpringApplicationBuilder configure(SpringApplicationBuilder application) { return application.sources(Application.class); } } 1234567891011 1234567891011

Application.class 为标注有@SpringBootApplication的主启动类

注意的问题

此时打成的包的名称应该和application.properties的 server.context-path=/spring-boot 保持一致

<build> <finalName>spring-boot</finalName> </build> 123 123

如果不一样发布到tomcat的webapps下上下文会变化

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