Tic-Tac-Toe

Tic-Tac-Toe

Kim likes to play Tic-Tac-Toe.

Given a current state, and now Kim is going to take his next move. Please tell Kim if he can win the game in next 2 moves if both player are clever enough.

Here “next 2 moves” means Kim’s 2 move. (Kim move,opponent move, Kim move, stop).

Game rules:

Tic-tac-toe (also known as noughts and crosses or Xs and Os) is a paper-and-pencil game for two players, X and O, who take turns marking the spaces in a 3×3 grid. The player who succeeds in placing three of their marks in a horizontal, vertical, or diagonal row wins the game.

Input

First line contains an integer T (1 ≤ T ≤ 10), represents there are T test cases.

For each test case: Each test case contains three lines, each line three string(“o” or “x” or “.”)(All lower case letters.)

x means here is a x

o means here is a o

. means here is a blank place.

Next line a string (“o” or “x”) means Kim is (“o” or “x”) and he is going to take his next move.

Output

For each test case:

If Kim can win in 2 steps, output “Kim win!”

Otherwise output “Cannot win!”

Sample Input 3 . . . . . . . . . o o x o o . x x x o x o x . . o . . . x o Sample Output Cannot win! Kim win! Kim win! #include <iostream> #include<algorithm> #include<stdlib.h> #include<stdio.h> #include<string.h> #include<math.h> #include<deque> #include<stack> using namespace std; char a[10][10],b; int main() { int T; scanf("%d",&T); while(T--) { int i,j; for(i=1;i<4;i++) for(j=1;j<4;j++) scanf(" %c",&a[i][j]); scanf(" %c",&b); if(a[2][2]==b&&((a[1][1]==b&&((a[1][3]=='.'||a[1][3]==b)&&(a[3][1]=='.'||a[3][1]==b)))||(a[3][3]==b&&((a[1][3]=='.'||a[1][3]==b)&&(a[3][1]=='.'||a[3][1]==b)))||(a[1][3]==b&&((a[1][1]=='.'||a[1][1]==b)&&(a[3][3]=='.'||a[3][3]==b)))||(a[3][1]==b&&((a[1][1]=='.'||a[1][1]==b)&&(a[3][3]=='.'||a[3][3]==b))))) printf("Kim win!\n"); else { int x=0,y=0,z=0; for(int k=1;k<4;k++) { x=0; y=0; if(a[k][1]=='.') x++; if(a[k][1]==b) y++; if(a[k][2]=='.') x++; if(a[k][2]==b) y++; if(a[k][3]=='.') x++; if(a[k][3]==b) y++; if(x==1&&y==2) z=1; if(y==3) z=1; //printf("%d %d\n",x,y); } for(int k=1;k<4;k++) { x=0; y=0; if(a[1][k]=='.') x++; if(a[1][k]==b) y++; if(a[2][k]=='.') x++; if(a[2][k]==b) y++; if(a[3][k]=='.') x++; if(a[3][k]==b) y++; if(x==1&&y==2) z=1; if(y==3) z=1; //printf("%d %d\n",x,y); } x=0; y=0; for(int k=1;k<4;k++) { if(a[k][k]=='.') x++; if(a[k][k]==b) y++; } //printf("%d %d\n",x,y); if(x==1&&y==2) z=1; if(y==3) z=1; x=0; y=0; for(int k=1;k<4;k++) { if(a[k][4-k]=='.') x++; if(a[k][4-k]==b) y++; } if(x==1&&y==2) z=1; if(y==3) z=1; //printf("%d %d\n",x,y); if(z==1) printf("Kim win!\n"); else printf("Cannot win!\n"); } } } 井字棋游戏。