N - A + B Again

B Again

题目描述

There must be many A + B problems in our HDOJ , now a new one is coming. Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too. Easy ? AC it !

Iutput

The input contains several test cases, please process to the end of the file. Each case consists of two hexadecimal integers A and B in a line seperated by a blank. The length of A and B is less than 15.

Output

For each test case,print the sum of A and B in hexadecimal in one line.

Sample Input

+A -A +1A 12 1A -9 -1A -12 1A -AA

Sample Output

0 2C 11 -2C -90

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思路：

http://blog.csdn.net/hyh863677698/article/details/79317819

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代码

#include<stdio.h> int main() { __int64 A,B; while(scanf("%I64X %I64X",&A,&B)!=EOF) { B=A+B; if(B>=0) printf("%I64X\n",B); if(B<0) { B=-B; printf("-%I64X\n",B); } } return 0; }