LeetCode 17. Letter Combinations of a Phone Number

xiaoxiao2021-02-28  41

题目

思路

DFS

代码

class Solution: def __init__(self): self.res_list = [] def dfs(self, digits, index, map_dict, tmp_list): if index == len(digits): self.res_list.append(''.join(tmp_list[:])) return for c in map_dict[digits[index]]: tmp_list.append(c) self.dfs(digits, index + 1, map_dict, tmp_list[:]) tmp_list.pop(-1) def letterCombinations(self, digits): """ :type digits: str :rtype: List[str] """ if not digits: return [] map_dict = {} map_dict['2'] = ['a','b','c'] map_dict['3'] = ['d','e','f'] map_dict['4'] = ['g','h','i'] map_dict['5'] = ['j','k','l'] map_dict['6'] = ['m','n','o'] map_dict['7'] = ['p','q','r','s'] map_dict['8'] = ['t','u','v'] map_dict['9'] = ['w','x','y','z'] self.dfs(digits, 0, map_dict, []) return self.res_list
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