Python 矩阵Numpy

xiaoxiao2021-02-28  23

import numpy as np a = np.array([(1,2),(-1,2)]) b = np.array([(2,3),(-1,2)]) #c = np.ones((2,2)) print(a) print(b) print('\n\n') #9-1 print(a + a) print(a * a.T) print(a.T * a) print(a * b) p = 1 x = np.array([(p,p),(p,p)]) print(a * (b - x)) #9-2 b0 = np.zeros(2) print(b0) print('\n\n') print(np.linalg.solve(b,b0)) #9-3 print(np.linalg.norm(a)) print(np.linalg.norm(b,ord=np.inf)) print(np.linalg.svd(b))#9-4x = np.diag((1,2,3)) i,j = np.linalg.eig(x)print(i)print(j)#9-5print(np.linalg.norm(a))#9-6print(np.minimum(a, 255)) G:\>python Num.py [[ 1 2] [-1 2]] [[ 2 3] [-1 2]] [[ 2 4] [-2 4]] [[ 1 -2] [-2 4]] [[ 1 -2] [-2 4]] [[2 6] [1 4]] [[1 4] [2 2]] [0. 0.] [0. 0.] 3.1622776601683795 5.0 (array([[ 0.92387953, 0.38268343], [ 0.38268343, -0.92387953]]), array([3.82842712, 1.82842712]), array([[ 0.38268343, 0.92387953], [ 0.92387953, -0.38268343]])) [1. 2. 3.] [[1. 0. 0.] [0. 1. 0.] [0. 0. 1.]] 3.1622776601683795 [[ 1 2] [-1 2]] print(np.linalg.svd(b))#9-4x = np.diag((1,2,3)) i,j = np.linalg.eig(x)print(i)print(j)#9-5print(np.linalg.norm(a))#9-6print(np.minimum(a, 255))

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