周测

xiaoxiao2021-02-28  47

-- 1、创建student和score表语句 CREATE TABLE t_student(     id              INT(10) PRIMARY KEY AUTO_INCREMENT,     name            VARCHAR(20) NOT NULL,     sex             VARCHAR(4),     birth           YEAR,     department      VARCHAR(20) NOT NULL,     address         VARCHAR(50) ); CREATE TABLE t_score(     id        INT(10) PRIMARY KEY AUTO_INCREMENT,     stu_id    INT(10) NOT NULL,     c_name    VARCHAR(20),     grade     INT(10) ); INSERT INTO t_student VALUES( 901,'张老大', '男',1985,'计算机系', '北京市海淀区'); INSERT INTO t_student VALUES( 902,'张老二', '男',1986,'中文系', '北京市昌平区'); INSERT INTO t_student VALUES( 903,'张三', '女',1990,'中文系', '湖南省永州市'); INSERT INTO t_student VALUES( 904,'李四', '男',1990,'英语系', '辽宁省阜新市'); INSERT INTO t_student VALUES( 905,'王五', '女',1991,'英语系', '福建省厦门市'); INSERT INTO t_student VALUES( 906,'王六', '男',1988,'计算机系', '湖南省衡阳市'); INSERT INTO t_score VALUES(NULL,901, '计算机',98); INSERT INTO t_score VALUES(NULL,901, '英语', 80); INSERT INTO t_score VALUES(NULL,902, '计算机',65); INSERT INTO t_score VALUES(NULL,902, '中文',88); INSERT INTO t_score VALUES(NULL,903, '中文',95); INSERT INTO t_score VALUES(NULL,904, '计算机',70); INSERT INTO t_score VALUES(NULL,904, '英语',92); INSERT INTO t_score VALUES(NULL,905, '英语',94); INSERT INTO t_score VALUES(NULL,906, '计算机',90); INSERT INTO t_score VALUES(NULL,906, '英语',85); -- 2、查询student表的所有记录 SELECT * FROM t_student; -- 3、查询student表的第2条到4条记录 SELECT * FROM t_student LIMIT 1,3; SELECT * FROM t_student LIMIT 1,3; -- 4、从student表查询所有学生的学号(id)、姓名(name)和院系(department)的信息 SELECT id,name,department FROM t_student ; -- 5、从student表中查询计算机系和英语系的学生的信息(用 IN 关键字) SELECT * FROM t_student WHERE department IN ('计算机系' OR '英语系'); -- 6、从student表中查询年龄18~22岁的学生信息(用 BETWEEN AND) SELECT * FROM t_student WHERE YEAR(NOW())-birth BETWEEN 28 AND 32; -- 7、从student表中查询每个院系有多少人 SELECT department,COUNT(id) FROM t_student GROUP BY department; -- 8、从score表中查询每个科目的最高分 SELECT c_name,MAX(grade) FROM t_score GROUP BY c_name; -- 9、查询李四的考试科目(c_name)和考试成绩(grade) SELECT s.name,sc.c_name,sc.grade FROM t_student AS s LEFT JOIN t_score AS sc ON s.id=sc.stu_id WHERE s.name='李四'; -- 10、用连接的方式查询所有学生的信息和考试信息 SELECT * FROM t_student AS s LEFT JOIN t_score AS sc ON s.id=sc.stu_id -- 11、计算每个学生的总成绩 SELECT s.name,SUM(grade) FROM t_student AS s LEFT JOIN t_score AS sc ON s.id=sc.stu_id GROUP BY s.name; -- 12、计算每个考试科目的平均成绩 SELECT sc.c_name,AVG(grade) FROM t_student AS s LEFT JOIN t_score AS sc ON s.id=sc.stu_id GROUP BY sc.c_name; -- 13、查询计算机成绩低于95的学生信息 SELECT * FROM t_student AS s LEFT JOIN t_score AS sc ON s.id=sc.stu_id WHERE sc.grade<=95 AND sc.c_name='计算机'; -- 14、查询同时参加计算机和英语考试的学生的信息 -- 第一种 SELECT *  FROM t_student  WHERE id IN  (SELECT stu_id  FROM t_score  WHERE c_name = '计算机' OR c_name = '英语'  GROUP BY stu_id  HAVING COUNT(*) = 2); -- 第二种 SELECT *  FROM t_student  WHERE id IN (SELECT stu_id  FROM t_score  WHERE stu_id  IN(SELECT stu_id FROM t_score WHERE c_name = '计算机') AND c_name = '英语'); -- 第三种 SELECT s.*  FROM t_student AS s, t_score AS b ,t_score AS c  WHERE s.id = b.stu_id AND b.c_name = '计算机' AND s.id = c.stu_id AND c.c_name = '英语'; -- 第一种 SELECT *  FROM t_student  WHERE id IN  (SELECT stu_id  FROM t_score  WHERE c_name = '计算机' OR c_name = '英语'  GROUP BY stu_id  HAVING COUNT(*) = 2); -- 第二种 SELECT *  FROM t_student  WHERE id IN (SELECT stu_id  FROM t_score  WHERE stu_id  IN(SELECT stu_id FROM t_score WHERE c_name = '计算机') AND c_name = '英语'); -- 第三种 SELECT s.*  FROM t_student AS s, t_score AS b ,t_score AS c  WHERE s.id = b.stu_id AND b.c_name = '计算机' AND s.id = c.stu_id AND c.c_name = '英语'; -- 15、将计算机考试成绩按从高到低进行排序 SELECT sc.c_name,sc.grade FROM t_score AS sc WHERE sc.c_name='计算机' ORDER BY sc.grade DESC; -- 16、从student表和score表中查询出学生的学号,然后合并查询结果 SELECT s.id FROM t_student AS s UNION SELECT sc.stu_id FROM t_score AS sc; -- 17、查询姓张或者姓王的同学的姓名、院系和考试科目及成绩 SELECT s.name,s.department,sc.c_name,sc.grade FROM t_student AS s LEFT JOIN t_score AS sc ON s.id=sc.stu_id WHERE s.name LIKE '张%' OR s.name LIKE '王%'; -- 18、查询都是湖南的学生的姓名、年龄、院系和考试科目及成绩 SELECT s.name,YEAR(NOW())-birth AS '年龄',s.department,sc.c_name,sc.grade FROM t_student AS s LEFT JOIN t_score AS sc ON s.id=sc.stu_id WHERE s.address LIKE '%湖南%'; SELECT s.name,YEAR(NOW())-birth AS '年龄',s.department,sc.c_name,sc.grade FROM t_student AS s LEFT JOIN t_score AS sc ON s.id=sc.stu_id

WHERE s.address LIKE '%湖南%';

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