python实现二叉树的操作(7种)

xiaoxiao2021-02-28  36

二叉树的前序遍历

递归

def preorder(root,res=[]): if not root: return res.append(root.val) preorder(root.left,res) preorder(root.right,res) return res

迭代

def preorder(root): res=[] if not root: return [] stack=[root] while stack: node=stack.pop() res.append(node.val) if node.right: stack.append(node.right) if node.left: stack.append(node,left) return res

二叉树的中序遍历

递归

def inorder(root,res=[]): if not root: return inorder(root.left,res) res.append(root.val) inorder(root.right,res) return res

迭代

def inorder(root): stack=[] node=root res=[] while stack or node: while node: stack.append(node) node=node.left node=stack.pop() res.append(node.val) node=node.right return res

二叉树的后序遍历

递归

def laorder(root,res=[]): if not root: return laorder(root.left,res) laorder(root.right,res) res.append(root.val) return res

迭代

def laorder(root): stack=[root] res=[] while stack: node=stack.pop() if node.left: stack.append(node.left) if node.right: stack.append(node.right) res.append(node.val) return res[::-1]

二叉树的层次遍历

迭代

def levelorder(root): queue=[root] res=[] while queue: node=queue.pop(0) if node.left: queue.append(node.left) if node.right: queue.append(node.right) res.append(node.val) return res
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