使用for循环的方式会出现索引溢出的情况
list1 = [i for i in range(0, 10)]
lenth = len(list1)
for j in range(0, lenth):
if list1[j] % 2 == 0:
del list1[j]
报错
Traceback (most recent call last):
File "F:/05 Python/pythoncode/paper_experience/mytest.py", line 6, in <module>
if list1[j] % 2 == 0:
IndexError: list index out of range
解决方法:
list1 = [i for i in range(0, 10)]
print(list1)
j=0
while j< len(list1):
if list1[j] % 2 == 0:
del list1[j]
j+=1
print(list1)
while循环中执行循环体之前会执行一次len方法