import os
a = 0
for i in range(1,5):
for j in range(1,5):
for k in range(1,5):
if (i!=j) and (i!= k) and (j!=k):
print i,j,k
a+=1
print a
#===>结果:24个互补相同的
1 2 31 2 41 3 21 3 41 4 21 4 32 1 32 1 42 3 12 3 42 4 12 4 33 1 23 1 43 2 13 2 43 4 13 4 24 1 24 1 34 2 14 2 34 3 14 3 224