阅读Java String源码遇到的问题

xiaoxiao2021-02-28  117

String源码

为什么contentEquals要加sunchronized,有什么意义吗 public boolean contentEquals(CharSequence cs) { // Argument is a StringBuffer, StringBuilder if (cs instanceof AbstractStringBuilder) { if (cs instanceof StringBuffer) { synchronized(cs) { return nonSyncContentEquals((AbstractStringBuilder)cs); } } else { return nonSyncContentEquals((AbstractStringBuilder)cs); } } // Argument is a String if (cs instanceof String) { return equals(cs); } // Argument is a generic CharSequence char v1[] = value; int n = v1.length; if (n != cs.length()) { return false; } for (int i = 0; i < n; i++) { if (v1[i] != cs.charAt(i)) { return false; } } return true; }

2、 compare方法中为什么比了一次小写之后还比了一次大写?

public int compare(String s1, String s2) { int n1 = s1.length(); int n2 = s2.length(); int min = Math.min(n1, n2); for (int i = 0; i < min; i++) { char c1 = s1.charAt(i); char c2 = s2.charAt(i); if (c1 != c2) { c1 = Character.toUpperCase(c1); c2 = Character.toUpperCase(c2); if (c1 != c2) { c1 = Character.toLowerCase(c1); c2 = Character.toLowerCase(c2); if (c1 != c2) { // No overflow because of numeric promotion return c1 - c2; } } } } return n1 - n2; }

原因:解决某些特殊字符存在的问题

// Unfortunately, conversion to uppercase does not work properly // for the Georgian alphabet, which has strange rules about case // conversion. So we need to make one last check before // exiting.

3、 indexOfSupplementary的使用场景,同理lastIndexOfSupplementary

private int indexOfSupplementary(int ch, int fromIndex) { if (Character.isValidCodePoint(ch)) { final char[] value = this.value; final char hi = Character.highSurrogate(ch); final char lo = Character.lowSurrogate(ch); final int max = value.length - 1; for (int i = fromIndex; i < max; i++) { if (value[i] == hi && value[i + 1] == lo) { return i; } } } return -1; }

4、 indexOf(char[] source, int sourceOffset, int sourceCount, char[] target, int targetOffset, int targetCount, int fromIndex)方法,通过判断target第一个字符是否鱼source相同,然后一位位判断,删掉判断条件之后,lastIndexOf也是同理

char first = target[targetOffset]; int max = sourceOffset + (sourceCount - targetCount); for (int i = sourceOffset + fromIndex; i <= max; i++) { /* Look for first character. */ if (source[i] != first) { while (++i <= max && source[i] != first); } /* Found first character, now look at the rest of v2 */ if (i <= max) { int j = i + 1; int end = j + targetCount - 1; for (int k = targetOffset + 1; j < end && source[j] == target[k]; j++, k++); if (j == end) { /* Found whole string. */ return i - sourceOffset; } } } return -1;

5、复制字符串的代码

public String concat(String str) { int otherLen = str.length(); if (otherLen == 0) { return this; } int len = value.length; char buf[] = Arrays.copyOf(value, len + otherLen); str.getChars(buf, len); return new String(buf, true); }
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