C++第4次实验(基础班)—循环结构程序设计(参考答案)-项目5:贪财的富翁

xiaoxiao2021-02-28  158

#include <iostream>  using namespace std;  int main( )  {      double m2f=1.0e5,f2m=0.01,m2fs=0,f2ms=0; //陌to富(m2f)每天1.0e5元,富to陌(f2m)第一天1分钱……      int day=1;//一定要赋初值      for(day=1;day<=30;day++)      {          m2fs+=m2f;          f2ms+=f2m;          f2m*=2;    //每天翻倍      }      cout<<"陌给富:"<<m2fs<<",富给陌:"<<f2ms<<endl;      if(m2fs>f2ms)          cout<<"陌生人输了";      else      {          if (m2fs<f2ms)              cout<<"富翁输了";          else              cout<<"两人持平,没意思的交易";      }         cout<<endl;      return 0;  }   

为使计算过程更清楚些,可以在循环中对每天的交易进行输出,程序如下:

 

 

 

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#include <iostream>  using namespace std;  int main( )  {      double m2f=1.0e5,f2m=0.01,m2fs=0,f2ms=0;      int day=1;//一定要赋初值      for(day=1;day<=30;day++)      {          m2fs+=m2f;          f2ms+=f2m;          f2m*=2;          cout<<"第"<<day<<"天,陌生人给富翁累计 "<<m2fs<<",富翁给陌生人累计 "<<f2ms<<endl;      }      cout<<"最终,陌生人给富翁:"<<m2fs<<",富翁给陌生人:"<<f2ms<<",";      if(m2fs>f2ms)          cout<<"陌生人输了";      else      {          if (m2fs<f2ms)              cout<<"富翁输了";          else              cout<<"两人持平,没意思的交易";      }         cout<<endl;      return 0;  }   
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