Java对【JSON数据的解析】--fastjson解析法

xiaoxiao2021-02-28  96

要求:解析下面JSON数据

String string = “{no:1,name:’Android’,employees:[{name:’zhangsan’,age:20},{name:’lisi’,age:21},{name:’wangwu’,age:22}]}”;


代码:

package com.qf.demo4; import java.util.ArrayList; import com.alibaba.fastjson.JSON; public class Test { public static void main(String[] args) { //fastjson解析数据 //1.阿里解析过程和Gson类似, String string= "{no:1,name:'android',employees:[{name:'zhangsan',age:20},{name:'lisi',age:21},{name:'wangwu',age:22}]}"; Employ employ = JSON.parseObject(string,Employ.class); System.out.println(employ); } } class Person{ private String name; private int age; public Person(String name, int age) { super(); this.name = name; this.age = age; } public Person() { super(); } public String getName() { return name; } public void setName(String name) { this.name = name; } public int getAge() { return age; } public void setAge(int age) { this.age = age; } @Override public String toString() { return "Person [name=" + name + ", age=" + age + "]"; } } class Employ{ private int no; private String name; private ArrayList<Person> employees; public Employ(int no, String name, ArrayList<Person> employees) { super(); this.no = no; this.name = name; this.employees = employees; } public Employ() { super(); } public int getNo() { return no; } public void setNo(int no) { this.no = no; } public String getName() { return name; } public void setName(String name) { this.name = name; } public ArrayList<Person> getEmployees() { return employees; } public void setEmployees(ArrayList<Person> employees) { this.employees = employees; } @Override public String toString() { return "Employ [no=" + no + ", name=" + name + ", employees=" + employees + "]"; } }
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