mysql查询日期补全(连续)方法

xiaoxiao2021-02-28  102

SELECT od.date, od.orderCount FROM ( SELECT DATE_FORMAT(order_time,'%Y-%m-%d') date, count(*) orderCount FROM order WHERE order_time>'开始时间' and order_time<'结束时间' GROUP BY DATE_FORMAT(order_time,'%Y-%m-%d') UNION (SELECT 0, '2017-03-01') UNION (SELECT 0, '2017-03-02') UNION (SELECT 0, '2017-03-03') UNION (SELECT 0, '2017-03-04') UNION (SELECT 0, '2017-03-05') UNION (SELECT 0, '2017-03-06') UNION (SELECT 0, '2017-03-07') UNION (SELECT 0, '2017-03-08') -- 很多个UNION ...... ) AS od GROUP BY od.date ORDER BY od.date ASC 如果有日期表那就用联表就行了,这里是不联表的方法,在程序上做处理后拼接到sql上 public function getLaidianLaifang($proj_ids, $start_date, $end_date, $gjfs, $type){ if(empty($proj_ids)){ return []; } $where = " and proj_id in ('".implode("','", $proj_ids)."')"; $rs = $this->dealDate($type, $start_date, $end_date); $group = $rs['group']; $union = $rs['union']; $sql = "select d.gj_cst_sum,d.date_type from (select count(DISTINCT opp_id) as gj_cst_sum,{$group} as date_type from s_opp2gjjl where gjfs = {$gjfs} and gj_date BETWEEN :start_date and :end_date {$where} GROUP BY {$group} {$union}) as d GROUP BY d.date_type ORDER BY d.date_type ASC"; return $this->kfsDb->createCommand($sql, [':start_date' => $start_date, ':end_date' => $end_date.' 23:59:59'])->queryAll(); } /** * 处理时间,把缺的补上 * */ private function dealDate($type, $start_date, $end_date, $proj = null){ $union = ''; $group = ''; if($type == 1){ $group = "HOUR(gj_date)"; for($i = 0; $i < 24; $i++){ $union .= " UNION (SELECT 0,{$i} {$proj})"; } }elseif($type == 3){ $group = "DATE(gj_date)"; for($i = $start_date; $i <= $end_date; $i++){ $union .= " UNION (SELECT 0, '{$i}' {$proj})"; } }elseif ($type == 4){ $group = "WEEK(gj_date,0)"; $s = date('W',strtotime($start_date)); $e = date('W',strtotime($end_date)); for($i = $s; $i <= $e; $i++){ $union .= " UNION (SELECT 0,{$i} {$proj})"; } }elseif ($type == 5){ $group = "MONTH(gj_date)"; $s = date('n',strtotime($start_date)); $e = date('n',strtotime($end_date)); for($i = $s; $i <= $e; $i++){ $union .= " UNION (SELECT 0,{$i} {$proj})"; } } return ['group' => $group, 'union' => $union]; }
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