由于只是调用服务，所以我这边只要实现一下spring环境下接入websevice就行了
第一种尝试的是使用spring ws的WebServiceTemplate
配置的方法如下：
? 1 2 3 < bean id = "xxxWebService" class = "org.springframework.ws.client.core.WebServiceTemplate" > < property name = "defaultUri" value = "http://XXX.net:8080" /> </ bean >第二种尝试我用了jaxws
配置方法如下：
? 1 2 3 4 5 < bean id = "xxxWebService" class = "org.springframework.remoting.jaxws.JaxWsPortProxyFactoryBean" > < property name = "serviceInterface" value = "com.xxx.UploadFileService" /> < property name = "namespaceUri" value = "http://XXX.net:8080" /> < property name = "wsdlDocumentUrl" value = "http://XXX.net:8080/XXXServicePort?WSDL" /> </ bean >第3种我尝试的是CXF
? 1 2 3 4 5 6 7 < import resource = "classpath:META-INF/cxf/cxf.xml" /> < import resource = "classpath:META-INF/cxf/cxf-extension-soap.xml" /> < import resource = "classpath:META-INF/cxf/cxf-servlet.xml" /> < jaxws:client id = "xxxWebService" serviceClass = "com.xxx.UploadFileService" address = "http://XXX.net:8080" > </ jaxws:client >第4种我用的是xfire，也是最后项目采用的方法
? 1 2 3 4 5 6 7 8 < bean id ="dwdsspWebService" class ="org.codehaus.xfire.spring.remoting.XFireClientFactoryBean"> < property name ="serviceClass"> < value >com.xxx.UploadFileService</ value > </ property > < property name ="wsdlDocumentUrl"> < value >http://XXX.net:8080/XXXServicePort?WSDL</ value > </ property > </ bean >参考文档：http://blog.csdn.net/kkdelta/article/details/3987591
http://blog.csdn.net/kkdelta/article/details/7290769
http://blog.csdn.net/jadyer/article/details/9002984
http://blog.csdn.net/vickychen89/article/details/6606571
http://coach.iteye.com/blog/894159
