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xiaoxiao2021-02-28  37

引入

先来看一道题:

如果 a+b+c=1000,且 a^2+b^2=c^2(a,b,c 为自然数),如何求出所有a、b、c可能的组合?

第一次尝试

import time start_time = time.time() # 注意是三重循环 for a in range(0, 1001): for b in range(0, 1001): for c in range(0, 1001): if a**2 + b**2 == c**2 and a+b+c == 1000: print("a, b, c: %d, %d, %d" % (a, b, c)) end_time = time.time() print("elapsed: %f" % (end_time - start_time)) print("complete!")

运行结果

a, b, c: 0, 500, 500 a, b, c: 200, 375, 425 a, b, c: 375, 200, 425 a, b, c: 500, 0, 500 elapsed: 214.583347 complete!

第二次尝试

import time start_time = time.time() # 注意是两重循环 for a in range(0, 1001): for b in range(0, 1001-a): c = 1000 - a - b if a**2 + b**2 == c**2: print("a, b, c: %d, %d, %d" % (a, b, c)) end_time = time.time() print("elapsed: %f" % (end_time - start_time)) print("complete!")

运行结果

a, b, c: 0, 500, 500 a, b, c: 200, 375, 425 a, b, c: 375, 200, 425 a, b, c: 500, 0, 500 elapsed: 0.182897 complete!
注意两次的运行时间
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