Given two lists Aand B, and B is an anagram of A. B is an anagram of A means B is made by randomizing the order of the elements in A.
We want to find an index mapping P, from A to B. A mapping P[i] = j means the ith element in A appears in B at index j.
These lists A and B may contain duplicates. If there are multiple answers, output any of them.
For example, given
A = [12, 28, 46, 32, 50] B = [50, 12, 32, 46, 28] We should return [1, 4, 3, 2, 0] as P[0] = 1 because the 0 th element of A appears at B[1] ,and P[1] = 4 because the 1 st element of A appears at B[4] ,and so on.Note:
A, B have equal lengths in range [1, 100].A[i], B[i] are integers in range [0, 10^5 这个问题首先把列表B 中元素生成一个字典，然后从字典中一次将列表A中元素取出，得到列表A中元素在列表B中的位置。 def mapping(self,A,B): D = {x:i for i,x in enumerate(B)} return(D[x] for x in A)